This video teaches how to use calculus find the position, velocity and acceleration of an object. Imagine an object moving on a straight line. It's position at any time (t) is given as s(t) pronounced "s of t". It's velocity is v(t)= s'(t) which is the derivative of s(t). It's acceleration a(t) is the derivative of its velocity v'(t). If we look at it from a different perspective we are differentiating. The derivative of the position is its velocity, the derivative of its velocity is it acceleration, etc. To go in the opposite direction we have to anti-differentiate. An example problem would be: An object is moving along a straight line with an acceleration of a(t)= 12t-6 ft/sec squared. If v(1)=9 ft/sec and s(1)=15 ft , find v(t) and s(t). He will solve the problem in a future video.

Get the latest from WonderHowTo on Facebook, Twitter, Pinterest, and Flipboard

## Be the First to Comment

## Share Your Thoughts