YouTube user NotesCollegeAlgebra teaches you how to evaluate combinations of functions from graphs. You start off with a graph and some functions. (f+g)(3), (g/f)(0) and (fg)(6). You start looking at the graph and the first line and you get (f+g)(3)=f(3)+g(3)=3+1=4. (g/f)(0)=g(0)/f(0)=2/3=2/3. (fg)(6)=f(6)g(6)=(3). But then when you want to find out g(6) you realize 6 is not in g's domain. So the answer to the last equation is that it doesn't exist.
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1 Comment
Thank you so much .. that really helped since i have a midtern in two days
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