How To: Calculate the age of the universe w/ Hubble's constant

Calculate the age of the universe w/ Hubble's constant

This is a great instructional video on how to calculate the age of Universe from Hubble's constant. The speed the galaxy moves away from us is directly proportional to the distance from us. Now think of big bang theory. Hubble's constant is equal to velocity over distance. 1 over Hubble's constant is equal to distance over velocity that is equal to time. Time equals to 1over 71. If you change it into all the same units words it is one over 71000 or 3.09x 10 to the power of 22. It is 3.09x10 to the power 22 over 71000 seconds. It is 3.09x10 to the power 22 over 71000 and 31,556,926 years. The age of Universe is 13.8 billion years.

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3 Comments

As far as I know, the latest discoveries suggest, that the speed with which distant galaxies are moving away from us is actually accelerating with increased distance. A graph describing the dependency is thus not a straight line, but a curve getting steeper and steeper (assuming x to be the distance and y to be the speed away from us), something resembling a parabel maybe.
An inevitable consequence of this must then be, that the universe is in fact much older than formerly believed (using the Hubble constant).
This might help overcomingh the present paradox,, that some objects in the universe seem to be older than the universe itself (or at least surprisingly old comparede to the age of the universe as such).

Hi, There is now a very simple way to calculate Hubble's Constant, by inputting to an equation, the numerical value of Pi and the speed of light (C) from Maxwell's equations. NO space probe measurements (with their inevitable small measuring / interpretation errors) are now required. Hubble's Constant is 'fixed' at 70.98047 PRECISELY. This maths method removes the errors / tolerances that is always a part of attempting to measuring something as 'elusive' as Hubble's Constant.

The equation to perform this can be found in 'The Principle of Astrogeometry' on Amazon Kindle Books, David.

from where u take t=1/71

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